(2x^2+7x+7)/x+2=0

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Solution for (2x^2+7x+7)/x+2=0 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(2*x^2+7*x+7)/x+2 = 0

(2*x^2+7*x+7)/x+(2*x)/x = 0

2*x^2+7*x+2*x+7 = 0

2*x^2+9*x+7 = 0

2*x^2+9*x+7 = 0

2*x^2+9*x+7 = 0

DELTA = 9^2-(2*4*7)

DELTA = 25

DELTA > 0

x = (25^(1/2)-9)/(2*2) or x = (-25^(1/2)-9)/(2*2)

x = -1 or x = -7/2

(x+7/2)*(x+1) = 0

((x+7/2)*(x+1))/x = 0

((x+7/2)*(x+1))/x = 0 // * x

(x+7/2)*(x+1) = 0

( x+1 )

x+1 = 0 // - 1

x = -1

( x+7/2 )

x+7/2 = 0 // - 7/2

x = -7/2

x in { -1, -7/2 }

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